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three resistors of 20. ohms, 30. ohms, and 60. ohms, respectively, are connected in series with a battery. a current of 2.0 amperes will flow through this circuit when the potential difference of the battery is a. 20.V b. 220 V c. 110 V d. 10.V.

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yamunasasidharan0808

Answer:

220 V

Explanation:

[tex]r_{1} = 20 ohm\\r_{2} = 30ohm\\r_{3} = 60ohm[/tex]

As the resistors are connected in series,

[tex]R_{eq} = r_{1} +r_{2} +r_{3}[/tex]

= 20 + 30 + 60

= 110 ohms

V = IR

= 2 * 110

= 220 V

Hope it helps

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