Answer:
Part A
The 10% rule is not met
Part B
The normal condition is not met
Step-by-step explanation:
The given data of the pieces of chocolate are;
The number of chocolates in the sample, n = 18
The number of white chocolate in the batch = 17
The number of dark chocolates in the batch = 43
Given that [tex]\hat p[/tex] is the proportion of white chocolates in the sample, we have;
The proportion of white chocolates in the batch, p = 17/60 = 0.28[tex]\overline 3[/tex]
Part A
The 10% condition states that the size of the sample should be less than or equal to 10% of the population because taking samples without replacing them does not result in independent Bernoulli trials
The given sample size, n = 18, which is 18/60×100 = 30% > 10% of the batch, therefore, the 10% rule is not met in the present situation
Part B
The normal approximation can be assumed when we have;
n·p > 10 and n·p·(1 - p) > 10
By plugging in the values for 'n' and 'p', we have;
p = 0.28[tex]\overline 3[/tex] = 17/60
n·p = 18 × 17/60 = 5.1 < 10
n·p·(1 - p) = 18 × 17/60 × (1 - 17/60) = 3.655 < 10
Therefore the normal condition is not met.