Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given: [tex]M_{1}[/tex] = 2.0 M, [tex]V_{1}[/tex] = ?
[tex]M_{2}[/tex] = 0.5 M, [tex]V_{2}[/tex] = 500 mL
Formula used to calculate the volume is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\2.0 M \times V_{1} = 0.5 M \times 500 mL\\V_{1} = 125 mL[/tex]
Thus, we can conclude that there is 125 mL of a 2.0 M [tex]CuCl_{2}[/tex] solution are needed to make 500 mL of a 0.5 M solution.
