Answer:
AC Midpoint (2,0)-
CB Midpoint (5,-4)
midlength is 5
Step-by-step explanation:
midpoint formula [tex](\frac{x_{1}+x_{2} }{2} ,\frac{y_{1} +y_{2} }{2})[/tex]
A(2,4) C(2,-4)
[tex]\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2} =\frac{0}{2} =0[/tex]
(2,0)
C(2,-4) B(8,-4)
[tex]\frac{8+2}{2} =\frac{10}{2} =5[/tex]
[tex]\frac{-4-4}{2} =\frac{-8}{2} =-4[/tex] midpoint is (5,-4)
Distance between the 2 midpoints is the midsegment
(2,0) and (5,-4)
[tex]d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1}) ^{2} }[/tex]
[tex]d=\sqrt{(5-2)^{2} +(-4-0)^{2} } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5[/tex]
