Answer:
c) [tex]\frac{x-2}{x+6}[/tex]
Step-by-step explanation:
When given that function (f) is the following,
[tex]f(x)=\frac{x+2}{x^2+4x-12}[/tex]
The wisest move to first make is to factor the expression, factoring is the process by which one rewrites a quadratic expression as the product of two linear expressions,
[tex]f(x)=\frac{x+12}{(x+6)(x-2)}[/tex]
If is given that function (g) is the following,
[tex]g(x)=\frac{4x^2-16x+16}{4x+48}[/tex]
Then one should also factor the expression,
[tex]g(x)=\frac{4(x-2)^2}{4(x+12)}[/tex]
One is asked to find the following,
[tex]f(x)*g(x)[/tex]
To do this operation, one must multiply the two functions together. It is easiest to do so when the functions are in factored form,
[tex]f(x)*g(x)[/tex]
Substitute,
[tex](\frac{x+12}{(x+6)(x-2)})(\frac{4(x-2)^2}{4(x+12)})[/tex]
Simplify, cross out like terms in the numerator and denominator,
[tex]\frac{x-2}{x+6}[/tex]
