Answer:
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Step-by-step explanation:
If θ is the angle between two vectors u and v, then cosθ = (u·v) / [llull llvll]
u·v = (2)(3) + (-4)(-8) = 38
llull = √[(2)2 + (-4)2] = √20 llvll = √[(3)2+(-8)2] = √73
So, cosθ = 38 / [√1460]
= 0.9945
θ = Cos-1(0.9945) ≈ 6.0°