Answer:
The force of gravity will be "0.11874 N"
Explanation:
The given values are:
Density of planet,
Q = 5000 Kg/m³
Inside radius,
r₀ = 1000 m
Now,
The mass of inside sphere will be:
⇒ [tex]m_p=density\times volume[/tex]
⇒ [tex]=5000\times \frac{4}{3}\pi r^3[/tex]
On putting the values, we get
⇒ [tex]=5000\times \frac{4}{3}\times \pi\times (1000)^3[/tex]
⇒ [tex]=85 \ kg[/tex]
hence,
The force of gravity will be:
= [tex]\frac{Gm_{planet} m_{person}}{r^2}[/tex]
= [tex]\frac{6.67\times 10^{-11}\times 5000\times 4\pi\times 85\times 1000}{3}[/tex]
= [tex]\frac{6.67\times 10^{-11}\times 4\pi\times 425000000}{3}[/tex]
= [tex]0.11874 \ N[/tex]
