Answer:
3.3 seconds
Step-by-step explanation:
v(t) =140t/5t - 6 where v is velocity
The time, t when, v = 44 ft/s
Put v = 44 ft/s in the equation :
44 = 140t / 5t - 6
44(5t - 6) = 140t
220t - 264 = 140t
-264 = 140t - 220t
-264 = - 80t
Divide both sides by 80
264 / 80 = 80t/80
3.3 = t
Hence, automobile will reach a velocity of 44 ft /s after 3.3 seconds
The elapsed time would the automobile reach a velocity of 44 Feet per second is 3.3 seconds
Since
An automobile's velocity, starting from a complete stop, is v(t) =140t/5t - 6 where v is measured in feet per second.
So, the time should be
[tex]44 = 140t \div 5t - 6[/tex]
44(5t - 6) = 140t
220t - 264 = 140t
-264 = 140t - 220t
-264 = - 80t
3.3 = t
Hence, The elapsed time would the automobile reach a velocity of 44 Feet per second is 3.3 seconds
learn more about time here: https://brainly.com/question/24308516
