I still don’t understand this very well I don’t know how to set up the equation. Pls help?
It’s trigonometry
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Answer:
[tex] \displaystyle x \approx 47.44[/tex]
Step-by-step explanation:
we are given a right angle triangle
we want to figure out x i.e hypotenuse
in order to do so we can consider trigonometry i.e sin
remember that,
[tex] \displaystyle \sin( \theta) = \frac{opp}{hypo} [/tex]
given that,theta=21° and opp=17 and hypo=x
Thus substitute:
[tex] \displaystyle \sin( {21}^{ \circ} ) = \frac{17}{x} [/tex]
cross multiplication:
[tex] \displaystyle x\sin( {21}^{ \circ} ) = {17}[/tex]
divide both sides by sin21°:
[tex] \displaystyle x \frac{\sin( {21}^{ \circ} ) }{ \sin( {21}^{ \circ}) }= \frac{17}{ \sin( {21}^{ \circ} ) }[/tex]
By using calculator we acquire:
[tex] \displaystyle x \approx 47.44[/tex]