A triangle has vertices (0, 2), (3, 1), and (6.2). What is the approximate perimeter of the triangle? Round your answer to the nearest hundredth.​

Respuesta :

Answer:

6 + 2√10 units.

Step-by-step explanation:

We can use the distance formula to find the distance between the points. The points are ,

  • (0,2)
  • (3,1)
  • (6,2)

Distance 1 :-

=> D₁ = √{ (x₁ - x₂ )² + ( y₁ - y₂ )² }

=> D₁ = √{ (0-3)² + (2-1)² }

=> D₁ = √{ 3² + 1² }

=> D₁ = √{ 9+1}

=> D = 10

Distance 2:-

=> D₂ = √{ (x₁ - x₂ )² + ( y₁ - y₂ )² }

=> D₂ = √{ (6-3)² + (2-1)² }

=> D₂ = √{ 3² + 1² }

=> D₂ = √{ 9 + 1}

=> D = 10

Distance 3 :-

=> D₃ = √{ (x₁ - x₂ )² + ( y₁ - y₂ )² }

=> D₃ = √{ (6-0)²+(2-2)²

=> D₃ = √6²

=> D = 6

→ Perimeter = D₁ +D₂ + D₃

→ Perimeter = √10 + √10 + 6

Perimeter = 6 + 210 units

Hence the perimeter is 6+210 units.