Answer: The space occupied by the gas at 400 torr and [tex]25^{o}C[/tex] is 250 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 250 mL, [tex]P_{1}[/tex] = 800 torr, [tex]T_{1} = 50^{o}C[/tex]
[tex]V_{2} = ?[/tex], [tex]P_{2}[/tex] = 400 torr, [tex]T_{2} = 25^{o}C[/tex]
Formula used is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL[/tex]
Thus, we can conclude that space occupied by the gas at 400 torr and [tex]25^{o}C[/tex] is 250 mL.
