Answer:
x = [tex]3\sqrt{13}[/tex] = 10.8
Step-by-step explanation:
Both problems are done the same way. I will do the first one and you do the second one. OK?
Move the radius x to make a right triangle. The 6 unit segment bisects the chord. So, the legs of the right triangle are 6 and 9
The use the Pythagorean theorem to find x, which is the hypotenuse of the right triangle. Now,
[tex]6^{2} + 9^{2} = x^{2}[/tex]
[tex]x^{2} = 36 + 81 = 117\\x = \sqrt{117} = 3\sqrt{13}[/tex]= 10.8
None of the answer choices are to the nearest tenth. So, I am confused about that.
In the second problem, the answer should be 11.2
