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2. If a gas at 500 mL has a temperature of 45°C, then what is the new volume when the temperature is increased to 65°C? Show your work.

Respuesta :

Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= [tex]\frac{V1 * T2}{T1}[/tex]= [tex]\frac{0.5 L * 338K}{318K}[/tex] = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml

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