Respuesta :
A point that has the polar coordinate [tex](r,\theta)[/tex] can also be represented by [tex](r, \theta+2n\pi)[/tex] and [tex](-r, \theta+(2n+1)\pi)[/tex].
From the list of given options, [tex](r,\theta)[/tex] and [tex](-r, \theta+\pi)[/tex] are represents the same point
Recall that:
[tex](r, \theta+2n\pi)[/tex] and [tex](-r, \theta+(2n+1)\pi)[/tex] represents the same point
Where n is an integer
Assume [tex]n = 0[/tex]
[tex](r, \theta+2n\pi)[/tex] becomes
[tex](r, \theta+2n\pi) = (r, \theta+2\times 0 \times \pi)[/tex]
[tex](r, \theta+2n\pi) = (r, \theta+0)[/tex]
[tex](r, \theta+2n\pi) = (r, \theta)[/tex]
Similarly,
[tex](-r, \theta+(2n+1)\pi)[/tex] becomes
[tex](-r, \theta+(2n+1)\pi)=(-r, \theta+(2\times 0+1)\pi)[/tex]
[tex](-r, \theta+(2n+1)\pi)=(-r, \theta+(0+1)\pi)[/tex]
[tex](-r, \theta+(2n+1)\pi)=(-r, \theta+(1)\pi)[/tex]
[tex](-r, \theta+(2n+1)\pi)=(-r, \theta+\pi)[/tex]
This means that: [tex](r,\theta)[/tex] and [tex](-r, \theta+\pi)[/tex] represent the same point.
Hence, (d) is correct.
Read more about polar coordinates at:
https://brainly.com/question/13206882
Answer:
There are two correct answers, (r,theta) and (r,theta+2pi) and (r,theta) and (-r,theta+pi)
Step-by-step explanation:
(r,theta) and (r,theta+2pi) is correct because you can add 2pi as many times as you want and it will still be true, as 2pi is a full circle in radians.
(r,theta) and (-r,theta+pi) is true because you can add pi, or 180°, to any polar coordinate and negate the r to make it equivalent, which is exactly what this answer does.
(these are also the right answers on a.pex :) )
good luck!