Use law of sines or law of cosines to find the length of side AB Please show work !!
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Answer:
[tex]AB = 11.3[/tex]
Step-by-step explanation:
Given
The attached triangle
Required
Length AB
To do this, we make use of sine law which is represented as:
[tex]\frac{a}{\sin(a)} = \frac{b}{\sin(b)} = \frac{c}{\sin(c)}[/tex]
So, we have:
[tex]\frac{15}{\sin(70)} = \frac{AB}{\sin(45)}[/tex]
Make AB the subject
[tex]AB = \frac{15}{\sin(70)} * \sin(45)[/tex]
[tex]AB = \frac{15}{0.9397} *0.7071[/tex]
[tex]AB = 11.3[/tex]