Given:
Renee has dimes and quarters in her wallet that total $1.60.
She has 2 more dimes than quarters.
To find:
The number of each type of coins.
Solution:
Let x be the number of dimes and y be the number of quarters.
She has 2 more dimes than quarters. So,
[tex]x=y+2[/tex] ...(i)
We know that,
1 dime = $0.10
1 quarter = $0.25
Renee has dimes and quarters in her wallet that total $1.60. So,
[tex]0.10x+0.25y=1.60[/tex] ...(ii)
From (i) and (ii), we get
[tex]0.10(y+2)+0.25y=1.60[/tex]
[tex]0.10y+0.20+0.25y=1.60[/tex]
[tex]0.35y=1.60-0.20[/tex]
[tex]0.35y=1.40[/tex]
Divide both sides by 0.35.
[tex]y=\dfrac{1.40}{0.35}[/tex]
[tex]y=4[/tex]
Substituting [tex]y=4[/tex] in (i), we get
[tex]x=4+2[/tex]
[tex]x=6[/tex]
Therefore, the number of dimes is 6 and the number of quarters is 4.
