[tex]\sf{3. \ \ Given : \dfrac{2}{3} - \dfrac{5}{4} + \dfrac{7}{2}}[/tex]
Let us solve the first two fractions : The LCM of 3 and 4 is 12
[tex]\sf{\implies \dfrac{4(2) - 5(3)}{12} + \dfrac{7}{2}}[/tex]
[tex]\sf{\implies \dfrac{8 - 15}{12} + \dfrac{7}{2}}[/tex]
[tex]\sf{\implies \dfrac{-7}{12} + \dfrac{7}{2}}[/tex]
LCM of 2 and 12 is 12
[tex]\sf{\implies \dfrac{-7 + 7(6) }{12}}[/tex]
[tex]\sf{\implies \dfrac{-7 + 42}{12}}[/tex]
[tex]\sf{\implies \dfrac{35}{12}}[/tex]
[tex]\sf{\implies 2 +\dfrac{11}{12}}[/tex]
[tex]\sf{\implies 2 \dfrac{11}{12}}[/tex]
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[tex]\sf{4. \ \ Given : \dfrac{(2 - 7)^2 + 5}{3}}[/tex]
[tex]\sf{\implies \dfrac{(-5)^2 + 5}{3}}[/tex]
[tex]\sf{\implies \dfrac{25 + 5}{3}}[/tex]
[tex]\sf{\implies \dfrac{30}{3}}[/tex]
[tex]\sf{\implies 10}[/tex]
