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Loud speaker A vibrates 200 times each second. Loud speaker B vibrates 400 times each second.a)What is the frequency of the sound produced by Loud speaker A ? Give the value and unit.
b)Which loudspeaker produces higher frequency of vibrations?
(Show calculations)

Respuesta :

Answer:

For a: The frequency produced by loudspeaker A is 200 Hz

For b: Loudspeaker B produces a higher frequency of vibrations.

Explanation:

To calculate the frequency of a loudspeaker, we use the formula:

[tex]\nu=\frac{\text{Number of vibrations}}{\text{Time period}}[/tex]          ......(1)

where,

[tex]\nu[/tex] = frequency

  • For loudspeaker A:

Number of vibrations = 200

Time period =  1 second

Putting values in equation 1:

[tex]\nu_A=\frac{200}{1s}=200Hz[/tex]

  • For loudspeaker B:

Number of vibrations = 400

Time period =  1 second

Putting values in equation 1:

[tex]\nu_B=\frac{400}{1s}=400Hz[/tex]

Hence, the frequency produced by loudspeaker A is 200 Hz and loudspeaker B produces a higher frequency of vibrations.

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