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If 5.0 grams of an unknown metal cools from 35.0°C to 22.6°C and loses 23.6 joules of heat, What is the specific heat of the metal, and what metal might the sample be?Immersive Reader

A)3.8 x 10^2 J/(g°C), gold

B)0.076 J/(g°C), mercurry

C)0.62 J/(g°C), iron

D)0.38 J/(g°C), copper

Respuesta :

abidemiokin

Answer:

3.8*10^2J/(g°C),

Step-by-step explanation:

Heat Energy = mcΔt

23.6 = 5c(35-22.6)

23.6 = 5c(12.4)

23.6 = 62c

c = 23.6/62

c = 0.3806

c = 3.8*10^2J/(g°C),gold

Hence the specific heat of the metal is 3.8*10^2J/(g°C),

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