Answer:
[tex]1 \: litre \: contain \: 0.10 \: moles \: of \: hydrochloric \: acid \\ 0.75 \: litres \: contain \: (0.75 \times 0.10) \: moles \\ = 0.075 \: moles \\ total \: volume = 0.75 + 0.35 \\ = 1.1 \: litres \\ 1.1 \: litres \: contain \: 0.075 \: moles \\ 1 \: litres \: will \: contain \: ( \frac{1 \times 0.075}{1.1} ) \\ = 0.068 \: mol \: {l}^{ - 1} [/tex]
