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If a truck starts from rest and it has acceleration of 4m/s^2 for 5 seconds and calculate it's final velocity . What will be the distance travelled by th truck during the time interval ?

Respuesta :

Answer:

final velocity:

[tex]v = u + at \\ v = 0 + (4 \times 5) \\ v = 20 \: m {s}^{ - 1} [/tex]

distance:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = (0 \times t) + \frac{1}{2} (4 \times {5}^{2} ) \\ s = 50 \: m[/tex]

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