Answer:
[tex]sin \theta = \frac{3}{5}[/tex]
Step-by-step explanation:
[tex]cos \theta = \frac{12}{15}\\\\cos^2 \theta = 1 - sin^2 \theta\\\\sin^2\theta = 1 - cos^2 \theta\\\\[/tex]
[tex]= 1 - (\frac{12}{15})^2\\\\= 1 - \frac{144}{225}\\\\= \frac{225 - 144}{225}\\\\=\frac{81}{225}[/tex]
[tex]sin \theta = \sqrt{\frac{81}{225}} = \frac{9}{15} = \frac{3}{5}[/tex]
