Answer:
184.1
Step-by-step explanation:
You have 4 different areas you need to look at. 1 half circle with a diameter of 8, a triangle with a height of 5, base of 6 and right angle, a rectangle with the measures of 8 and 9 and another rectangle with measures of 6 and 12
Circle:
[tex]A = \pi r^{2} \\A = \pi 4^{2} \\A = 50.265[/tex]
Area of the half circle is 25.1325
Triangle:
[tex]A = h\frac{b}{2} \\A = 5 \frac{6}{y} \\A = 15[/tex]
Area of the triangle is 15
Rectangle:
[tex]A = wl\\A = 9*8\\A = 72[/tex]
Area of first rectangle is 72
Area of 2nd rectangle is using 6 and 12 = 72
Now add all together for your total area
