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If a sample of oxygen has a volume of 160 L at 91 degrees celsius what will the oxygen be when the temperature drops to 0.00 degrees celsius.

Respuesta :

dsdrajlin

Answer:

120 L

Explanation:

Step 1: Given data

  • Initial volume (V₁): 160 L
  • Initial temperature (T₁): 91 °C
  • Final volume (V₂): ?
  • Final temperature (T₂): 0.00 °C

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 91°C + 273.15 = 364 K

K = 0.00°C + 273.15 = 273.15 K

Step 3: Calculate the final volume occupied by the oxygen

Assuming ideal behavior and constant pressure, we can calculate the final volume occupied by the oxygen using Charles' law.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 160 L × 273.15 K/364 K = 120 L

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