Answer:
The buoyant force on the piece of iron is 3.5 newtons.
Explanation:
According to the Archimedes' Principle, the piece of metal experiments a buoyant force equal to the weight of the displaced fluid. By Newton's Laws, we have the following formula:
[tex]F_{B} - W_{P}+W_{F} = 0[/tex] (1)
Where:
[tex]F_{B}[/tex] - Buoyant force on the piece of iron, in newtons.
[tex]W_{P}[/tex] - Weight of the piece of metal, in newtons.
[tex]W_{F}[/tex] - Weight of the fluid displaced by the piece of metal, in newtons.
[tex]F_{B} = W_{P}-W_{F}[/tex]
If we know that [tex]W_{P} = 6.5\,N[/tex] and [tex]W_{F} = 3\,N[/tex], then the buoyant force on the piece of iron is:
[tex]F_{B} = 6.5\,N - 3\,N[/tex]
[tex]F_{B} = 3.5\,N[/tex]
The buoyant force on the piece of iron is 3.5 newtons.
