Respuesta :

tqiu
Difference of squares gives:
(4x)^2-3^2
=16x^2-9

Answer:

[tex]16^{2} - 9[/tex]

Step-by-step explanation:

[tex](4x + 3)(4x - 3)[/tex]

Step 1: Multiply [tex]4x[/tex] to [tex](4x - 3)[/tex], you get, [tex]16x^2 -12x[/tex]

Step 2: Multiply [tex]3[/tex] to [tex](4x - 3)[/tex], you get, [tex]12x - 9[/tex]

[tex]16x^2 - 12x +12x - 9[/tex]

Step 3: add or subtract the numbers with the same variables together

[tex]16x^2 - 9[/tex] is your final answer