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11-06-2021
Mathematics

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What is the product?

(4y − 3)(2y2 + 3y − 5)

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nesa1974p5whmu nesa1974p5whmu

11-06-2021

(4y−3)(2y^2+3y−5)
=(4y+−3)(2y^2+3y+−5)

=(4y)(2y^2)+(4y)(3y)+(4y)(−5)+(−3)
(2y^2)+(−3)(3y)+(−3)(−5)

=8y^3+12y^2-20y-6y^2-9y+15

=8y^3+6y^2-29y+15

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