contestada

Find the equation of the line through (6,8) which is parallel to the line y=4x−6.

Give your answer in the form y=mx+b.

Respuesta :

Answer:

[tex]y=4x-16[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

  • Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope of the line and b is the y-intercept (the value of y when x is 0)
  • Parallel lines always have the same slope

1) Determine the slope (m)

[tex]y=4x-6[/tex]

4 is in the place of m, making it the slope. Because parallel lines have the same slope, the slope of the line is therefore 4. Plug this into [tex]y=mx+b[/tex]:

[tex]y=4x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=4x+b[/tex]

Plug in the given point (6,8) and solve for b

[tex]8=4(6)+b\\8=24+b[/tex]

Subtract 24 from both sides to isolate b

[tex]8-24=24+b-24\\-16=b[/tex]

Therefore, the y-intercept of the line is -16. Plug this back into [tex]y=4x+b[/tex]:

[tex]y=4x-16[/tex]

I hope this helps!