Answer:
side AC =[tex]10\sqrt{3}[/tex] , angle A=30 degree , angle B=60 degree
Step-by-step explanation:
using pythagors theorem
a^2 + b^2 =c^2
here a and b are the legs of the triangle whereas c is hypotenuse so,
10^2 + AC^2 = 20^2
100 + AC^2 = 400
AC^2 =400-100
AC^2 =300
AC=[tex]\sqrt{300}[/tex]
AC=[tex]10\sqrt{3}[/tex]
For angle A
take angle A as reference angle
using sin rule
sin A =opposite/hypotenuse
sin A=[tex]\frac{10}{20}[/tex]
sin A=[tex]\frac{1}{2}[/tex]
A=[tex]sin^{-1} (\frac{1}{2} )[/tex]
A=30 degree
For angle B
angle A + angle B + angle C =180 degree (sum of interior angles of a triangle)
30 + angle B + 90=180
120 + angle B =180
angle B =180-120
angle B =60 degree
