A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of the entire rectangle. Your answer should be a polynomial in standard form.

Respuesta :

Answer: [tex]k^4+10k^3+21k^2[/tex]

Step-by-step explanation:

Given

Height of rectangle is [tex]h=k^2+3k[/tex]

Width is [tex]w=k^2+7k[/tex]

The area of the rectangle is given by the multiplication of the height and width

[tex]\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2[/tex]

Thus, the area of the rectangle is [tex]k^4+10k^3+21k^2[/tex].