A cone with a base circumference of 6 pi and a height equal to half the radius. The volume of the cone is 42.39.
The volume of the cone is the product of one-third of the height, pie, and square of the radius.
The volume of the cone = 1/3 [tex]\pi r^{2} h[/tex]
A cone with a base circumference of 6 pi and a height equal to half the radius.
The circumference of the circular base = 2πr
6π = 2πr
r = 3
The radius of the circular base of a cone is 3 unit.
A height equal to half the radius. Thus, the height is 1.5
The volume of the cone = 1/3 [tex]\pi r^{2} h[/tex]
= 1/3 (3.14) (9)(1.5)
= 42.39
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