One day Mr. Bakare poses a particularly challenging problem, and his random name generator produces a team of 4 students that includes 2 of the 3 top students in the class. What is the probability that a randomly selected group of 4 students will include 2 of the 3 strongest students

Respuesta :

Answer:

The correct answer is "0.0536".

Step-by-step explanation:

According to the question,

The probability of 2 of strongest 3 included will be:

P = [tex]\frac{(Number \ of \ ways \ of \ choosing \ 2 \ out \ of \ 3)\times (Number \ of \ ways \ of \ choosing \ 2 \ out \ of \ 20)}{Number \ of \ ways \ of \ choosing \ 4 \ people \ out \ of \ 24}[/tex]

By substituting the values, we get

  = [tex]\frac{\binom{3}{2} \binom{20}{2}}{\binom{24}{4}}[/tex]

  = [tex]0.0536[/tex]

Thus the above is the correct solution.