Because the variable has an even power, we will see that:
- As x approaches -∞, h(x) approaches -∞
- As x approaches ∞, h(x) approaches -∞.
What is the end behavior of h(x)?
Here we have h(x) = -4x^2 + 11
Notice that the variable is squared, this means that the sign does not matter, the outcome of:
-4x^2 will always be negative. So in both ends (when x tends to infinity and negative infinity), we will have the same end behavior.
When we take that limit, -4x^2 will just tend to negative infinity, then in both cases, the function tends to negative infinity.
So we have:
- As x approaches negative infinity, h(x) approaches negative infinity.
- As x approaches positive infinity, h(x) approaches negative infinity.
If you want to learn more about limits, you can read:
https://brainly.com/question/5313449