Answer:
[tex] \frac{15 \sqrt{209} }{209} [/tex]
Step-by-step explanation:
Objective: Understand and work with trig identies.
Recall multiple trig identies and manipulate them to get from cosecant to secant.
Given
[tex] \csc(a) = \frac{60}{16} [/tex]
Apply reciprocal identity csc a = 1/sin a.
[tex] \sin(a) = \frac{16}{60} [/tex]
Apply pythagorean identity to find cos a.
[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]
[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]
[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]
We can simplify both expression
[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]
[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]
Cosine is positve on quadrant 1 so that cos(a)
Apply reciprocal identity sec a= 1/ cos a.
The answer is
[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]
Rationalize the denominator.
[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]
