Answer:
yes, and it's in intercept form
Step-by-step explanation:
Hi there!
We are given the function f(x)=-2(x-4)(x+3)
A quadratic function is a function that has a degree of 2 (the highest exponent in the function is to the 2nd power)
There are 3 forms to write a quadratic function:
standard form, which is f(x)=ax²+bx+c, where a, b, and c are free coefficients (numbers)
vertex form, which is f(x)=a(x-h)²+k, where a is a free coefficient and (h,k) is the vertex
intercept form, which is f(x)=a(x-[tex]x_{1}[/tex])(x-[tex]x_{2}[/tex]), where a is a free coefficient and [tex]x_{1}[/tex] and [tex]x_{2}[/tex] are the x intercepts
You may notice that f(x)=-2(x-4)(x+3) is actually in intercept form; a is -2 and [tex]x_{1}[/tex] and [tex]x_{2}[/tex] are 4 and -3 respectively (remember: the formula for intercept form has -[tex]x_{1}[/tex] and -[tex]x_{2}[/tex], but the x intercepts are [tex]x_{1}[/tex] and [tex]x_{2}[/tex]. Therefore, the x intercepts should be the opposites of -[tex]x_{1}[/tex] and -[tex]x_{2}[/tex]).
If the formula is in intercept form, it should be quadratic.
However, if you want to be sure it's quadratic, you can expand the function.
f(x)=-2(x-4)(x+3)
first, multiply the binomials together using FOIL
(x-4)(x+3)
x²-x-12
now multiply x²-x-12 by -2
-2(x²-x-12)
do the distributive property
-2x²+2x+24
It's a quadratic function! The value of the highest exponent is 2 :)
Hope this helps!
