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Mrs. Law’s seventh grade class volunteers for two days at an animal shelter. Each day, 30% of students will be assigned to help groom animals, 50% will be assigned to walk animals, and 20% will be assigned to clean the kennels. Michaela designs a simulation to determine how likely it is that she will be assigned to walk animals both days. She assigns digits as follows:��� 0, 1, 2 5 Grooming• 3, 4, 5, 6, 7 5 Walking• 8, 9 5 Cleaning Then she generates the following sets of random numbers for her simulation. 2, 9 5, 2 3, 9 0, 1 8, 3 0, 5 0, 5 8, 3 6, 8 4, 7 7, 4 1, 5 Based on the results of the simulation, what is the probability that Michaela will walk animals on: a. both days? b. one day only? c. at least one day?

Respuesta :

Michaela will walk the dogs B only 1 day only

Based on the results of the simulation, the probability that Michaela will walk animals on:

a. both days = 1/6

b. one day only = 2/3

c. at least one day = 5/6

What is probability?

Probability is simply how likely something is to happen.

Grooming = 0, 1, 2

Walking = 3, 4, 5, 6, 7

Cleaning = 8, 9

Based on the data generated in simulation, categorizing it into "Michael will walk animals zero days/ one day only/ both days based on the digit categorization given above.

(2,9) - zero days

(5,2) - one day

(3,9) - one day

(0,1) - zero days

(8,3) -one day

(0,5) - one day

(8,3) - one day

(6,8) - one day

(4,7) - two days

(7,4) - two days

(1,5) - one day

Probability that Michaela will walk animals both days = [tex]\frac{2}{12} = \frac{1}{6}[/tex]

Probability that Michaela will walk animals one day only = [tex]\frac{8}{12} = \frac{2}{3}[/tex]

Probability that Michaela will walk animals at least one day = Probability that Michaela will walk animals one day only + Probability that Michaela will walk animals two days only  = [tex]\frac{8}{12}+ \frac{2}{12} = \frac{10}{12} = \frac{5}{6}[/tex]

Learn more about probability here

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