Respuesta :
Answer:
[tex]1 \: mole \: of \: sulphurdioxide \: weighs \: 64 \: g \\ 0.850 \: moles \: will \: weigh \: (0.850 \times 64) \: g \\ = 544 \: g[/tex]
The mass of 0.85 mol of sulfur dioxide has been 54.4 grams.
Moles can be calculated as the ratio of the mass to the compound to the molecular mass. The moles can be expressed as:
Moles = [tex]\rm \dfrac{mass}{molecular\;mass}[/tex]
Mass = moles [tex]\times[/tex] molecular mass
The molecular mass of sulfur dioxide = Mass of sulfur + 2 [tex]\times[/tex] mass of oxygen
= 32 + 2 [tex]\times[/tex] 16
= 32 + 32
= 64 g/mol
The given moles of sulfur dioxide = 0.850 mol
The mass of sulfur dioxide = 0.850 [tex]\times[/tex] 64
The mass of sulfur dioxide = 54.4 grams.
The mass of 0.85 mol of sulfur dioxide has been 54.4 grams.
For more information about the moles of the compound, refer to the link:
https://brainly.com/question/11588323
