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A 5.4 kg bowling ball and a 2.7 gram ping-pong ball collide head-on. If the magnitude of the force by the bowling ball on the ping-pong ball is 3.5 N, what is the magnitude of the force by the ping-pong ball on the bowling ball

Respuesta :

onyebuchinnaji

Answer:

The magnitude of force of the ping-pong ball on the bowling ball , [tex]F_p[/tex] = 3.5 N

Explanation:

Given;

mass of the bowling ball, [tex]m_b[/tex] = 5.4 kg

mass of the ping-pong ball, [tex]m_p[/tex] = 2.7 g = 0.0027 kg

magnitude of force of the bowling ball, [tex]F_b[/tex] = 3.5 N

let the magnitude of force of ping-pong ball = [tex]F_p[/tex]

Apply Newton's third law of motion; action and reaction are equal and opposite.

[tex]F_b = -F_p[/tex]

The force of the ping-pong ball on the bowling ball is equal to that of the bowling ball on ping-pong ball, but in opposite direction.

Thus, the magnitude of force of the ping-pong ball on the bowling ball , [tex]F_p[/tex] = 3.5 N

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