23)
You have to use the Pythagoras theorem
hypotenuse²=leg₁²+leg₂²
In this case:
leg₁=80 yd
leg ₂= 60 yd
hypotenuse=diagonal
hypotenuse²=(80 yd)²+(60 yd)²
hypotenuse²=6400 yd²+3600 yd²
hypotenuse²=10000 yd²
hypotenuse=√(10000 yd²)=100 yd
answer: the length of the diagonal is 100 yards.
24)
You have to use the Pythagoras theorem
hypotenuse²=leg₁²+leg₂²
In this case:
leg₁=5 ft
leg ₂= 9 ft
hypotenuse= length of the string
hypotenuse²=(5 ft)²+(9 ft)²
hypotenuse²=25 ft²+81 ft²
hypotenuse²= 106 ft²
hypotenuse=√(106 ft²)=10.295... ft≈10.30 ft
answer: the length of the string is 10.30 ft.
