contestada

If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be
a. reduced one-half.
c. two times the original heat.
b. unchanged.
d. four times the original heat.

Respuesta :

mathssydney
Q=l^2 times R times t
Where Q - heat, I -current, R - resistance and t is time

If you increase I twice (and it's squared), than Q gonna went up 4 times (2 squared).

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Explanation:

It is given that,

Current, [tex]I_1=6\ A[/tex]

Heat produced, [tex]H_1=I_1^2Rt[/tex]............(1)      

Where

R is the resistance

t is the time taken

So, [tex]H_1=36Rt[/tex]

Current, [tex]I_2=12\ A[/tex]

Heat produced, [tex]H_1=I_2^2Rt[/tex]      

So, [tex]H_2=144Rt[/tex].............(2)

From equation (1) and (2), it is clear that

[tex]H_2=4\times H_1[/tex]

So, If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be four times the original heat.