Answer: The density of the cube of metal is [tex]8.91g/cm^3[/tex]
Explanation:
To calculate the volume of cube, we use the formula:
[tex]V=a^3[/tex]
where,
a = edge length of cube
Edge length of cube = 1.2 cm
Volume of cube = [tex](1.2)^3=1.728cm^3[/tex]
To calculate density of a substance, we use the equation:
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}[/tex]
We are given:
Mass of cube = 15.4 g
Volume of cube = [tex]1.728cm^3[/tex]
Putting values in above equation, we get:
[tex]\text{Density}=\frac{15.4g}{1.728cm^3}=8.91g/cm^3[/tex]
Hence, the density of the cube of metal is [tex]8.91g/cm^3[/tex]
We have that from the Question"Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g." it can be said that The density of the cube is
[tex]\rho=8912.0kg/m^3[/tex]
From the Question we are told
Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g.
Generally the equation for Density is mathematically given as
[tex]density=\frac{m}{v}\\\\\rho=\frac{15.4*(1/1000)}{(1.2/100)^3}[/tex]
[tex]\rho=8912.0kg/m^3[/tex]
Therefore
The density of the cube is
[tex]\rho=8912.0kg/m^3[/tex]
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