Hagrid
contestada

In the image, point A is the center of the circle. Which two line segments must be equal in length?

AH¯¯¯¯¯ and BC¯¯¯¯¯

HI¯¯¯¯ and BC¯¯¯¯¯

EF¯¯¯¯¯ and HI¯¯¯¯

EF¯¯¯¯¯ and AI¯¯¯¯

In the image point A is the center of the circle Which two line segments must be equal in length AH and BC HI and BC EF and HI EF and AI class=

Respuesta :

Nirina7
the answer

the true answer is  
EF¯¯¯¯¯ and HI¯¯¯¯
proof

the line EF passes on A, and so does the line HI. both line are called diameter of the circle, that means
EF = HI
JeanaShupp

Answer: [tex]\overline{EF}=\overline{HI}[/tex]

Step-by-step explanation:

Given: In the image, point A is the center of the circle.

Therefore every straight line segments passing from one to another point of circle through the center of circle A is the diameter of the circle.

Since, [tex]\overline{EF}[/tex] and  [tex]\overline{HI}[/tex] are the line segments passing from side to side of circle through the center of circle A is the diameter of the circle, then both are representing diameter of the given circle.

Since, all the diameter of a circle has a unique length .

Hence, the  line segments must be equal in length :

[tex]\overline{EF}=\overline{HI}[/tex]

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