Here, I've attached a picture of the triangle that accompanies this explanation.
cot = [tex] \frac{1}{tan} [/tex] = [tex] \frac{1}{ \frac{sin}{cos} } [/tex] = [tex] \frac{cos}{sin} [/tex]
Now view the triangle.
PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.
sin of the angle would be opposite/hypotenuse, so sin = [tex] \frac{1}{ \sqrt{10} } [/tex]
cos of the angle would be adjacent/hypotenuse, so cos = [tex] \frac{-3}{ \sqrt{10} } [/tex]
tan of the angle would be opposite/adjacent, so tan = [tex] - \frac{1}{3} [/tex]
