9514 1404 393
Answer:
C. (45+11i)/29
Step-by-step explanation:
Multiply numerator and denominator by the conjugate of the denominator.
[tex]\dfrac{5-7i}{2-5i}=\dfrac{(5-7i)(2+5i)}{(2-5i)(2+5i)}=\dfrac{(5)(2)+(-7i)(5i) +(5)(5i)+(-7i)(2)}{2^2+5^2}\\\\=\dfrac{(10+35)+(24-14)i}{29}=\boxed{\dfrac{45}{29}+\dfrac{11}{29}i}[/tex]
