Answer:
C.[tex]3.8\times 10^{-2}[/tex]
Explanation:
We are given that
Initial concentration, [tex][A]_o=4.3 M[/tex]
First half life, [tex]t_{\frac{1}{2}}=56[/tex]minutes
Second half life, [tex]t'_{\frac{1}{2}}=28[/tex]minutes
We have to find K.
The given reaction is zero order reaction.
We know that for zero order reaction
[tex]t_{\frac{1}{2}}=\frac{[A]_o}{2k}[/tex]
Using the formula
[tex]56=\frac{4.3}{2k}[/tex]
[tex]k=\frac{4.3}{2\times 56}[/tex]
[tex]k=3.8\times 10^{-2}[/tex]
Hence, option C is correct.
Zero-order reactions are the reactions when a surface or a catalyst is required for the reaction to proceed and is saturated by the reactant chemicals. The result of the concentration versus the time plot will be a straight line in a zero-order reaction.
[tex]3.8 \times 10 ^{-2}[/tex] is the value of k.
Given,
The given reaction in the question is of zero-order and for that, we know that,
[tex]t \dfrac{1}{2} = \dfrac{[A_{0}] }{2\;\rm k}[/tex]
Substituting the values in the equation we get:
[tex]\begin{aligned}56 &= \dfrac{4.3 }{2\; \rm k}\\\\\rm k &= {4.3 }{2 \times 56}\\\\\rm k &= 3.8 \times 10^{ -2}\end{aligned}[/tex]
Therefore, option C is correct.
Learn more about the zero-order reaction here:
https://brainly.com/question/4638382
