Answer:
The answer to your question is given below
Explanation:
The balanced equation for the reaction is given below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 2 moles of KCl and 3 moles of O₂.
Next, we shall determine the number of mole of KClO₃ that will decompose to produce 9 moles of O₂. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, Xmol of KClO₃ will decompose to produce 9 moles of O₂ i.e
Xmol of KClO₃ = (2 × 9)/3
Xmol of KClO₃ = 6 moles
Thus, 6 moles of KClO₃ is needed for the reaction.
Next, we shall determine the number of mole KCl that will be produced by the decomposition of 6 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 2 moles of KCl.
Therefore, 6 moles of KClO₃ will also decompose to produce 6 moles of KCl.
Finally we shall represent the reaction in a chart as illustrated below:
2KClO₃ —> 2KCl + 3O₂
6 moles —> 6 moles | 9 moles
