Answer:
The final speed of electron=[tex]5.93\times 10^6m/s[/tex]
Explanation:
We are given that
Initial velocity, u=0
Potential, V=100 V
We have to find the final speed.
Mass of electron, [tex]m=9.1\times 10^{-31} kg[/tex]
Charge on electron, q=[tex]1.6\times 10^{-19}C[/tex]
We know that
[tex]qV=\frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
Using the formula
[tex]1.6\times 10^{-19}\times 100=\frac{1}{2}\times 9.1\times 10^{-31} v^2-0[/tex]
[tex]v^2=\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}[/tex]
[tex]v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}}[/tex]
[tex]v=5.93\times 10^6m/s[/tex]
Hence, the final speed of electron=[tex]5.93\times 10^6m/s[/tex]
