Answer:
[tex]\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}[/tex]
Step-by-step explanation:
A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,
[tex]\rm\implies y = x^2+x - 6 [/tex]
Here we need to substitute the different values of x , to get the different values of y.
Put x = -3 :-
[tex]\rm\implies y = 3^2-3-6\\ [/tex]
[tex]\rm\implies y = 9 - 3 - 6 \\[/tex]
[tex]\rm\implies y = 0 [/tex]
Put x = -2 :-
[tex]\rm\implies y = 2^2-2-6\\ [/tex]
[tex]\rm\implies y = 4 -2-6\\[/tex]
[tex]\rm\implies y = -4 [/tex]
Put x = -1 :-
[tex]\rm\implies y = -1^2-1-6\\[/tex]
[tex]\rm\implies y = 1 -1-6 \\[/tex]
[tex]\rm\implies y = -6 [/tex]
Put x = 1 :-
[tex]\rm\implies y = 1^2+1-6\\ [/tex]
[tex]\rm\implies y = 2 -6[/tex]
[tex]\rm\implies y = -4[/tex]
Put x = 2 :-
[tex]\rm\implies y = 2^2+2-6\\ [/tex]
[tex]\rm\implies y = 4 +2-6\\ [/tex]
[tex]\rm\implies y = 2[/tex]
Put x = 3 :-
[tex]\rm\implies y = 3^2+3-6\\ [/tex]
[tex]\rm\implies y = 9 +3-6\\ [/tex]
[tex]\rm\implies y = 6 [/tex]
Final table :-
[tex]\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}[/tex]
