Answer:
p = -9 m
Explanation:
For this exercise we use the equation of the geometric optics constructor
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and the image, respectively.
The mirrors the focal length is
f = R / 2
f = 2/2
f = 1 m
the magnification is
m =[tex]\frac{h'}{h} = - \frac{q}{p}[/tex]
indicates that the image was reduced h ’= h/10 implies that m = 1/10
[tex]\frac{1}{10} = - \frac{q}{p}[/tex]
we write our system of equations
p = -10q
1/1 = [tex]\frac{1}{p} + \frac{1}{q}[/tex]
we substitute
1 = [tex]\frac{1}{p} - \frac{10}{p}[/tex]
1 = 1/p (1 - 10)
1 = -9 / p
p = -9 m
