Answer:
[tex]V_1 = {2 \: m}^{3} [/tex]
[tex]T_1 = 303 \: k[/tex]
[tex]V_2 = 2(V_1) = 2(2) = 4 \: {m}^{3} [/tex]
[tex]T_2 = ?[/tex]
Here, it's mentioned that the pressure is constant.
By Charles law :
[tex]\implies V \propto T \\ [/tex]
[tex]\implies \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2} \\ [/tex]
[tex]\implies \dfrac{2}{4} = \dfrac{303}{T_2} [/tex]
[tex]\implies \dfrac{T_2}{4} = \dfrac{303}{2} [/tex]
[tex]\implies T_2 = \dfrac{303 \times 4}{2} [/tex]
[tex]\implies T_2 = \dfrac{1212}{2} [/tex]
[tex]\implies T_2 = 606 \: k [/tex]
